(16x)^2+(9x)^2=6606,4384

Solution for (16x)^2+(9x)^2=6606,4384 equation:

(16x)^2+(9x)^2=6606.4384

We move all terms to the left:

(16x)^2+(9x)^2-(6606.4384)=0

We add all the numbers together, and all the variables

25x^2-6606.4384=0

a = 25; b = 0; c = -6606.4384;
Δ = b2-4ac
Δ = 02-4·25·(-6606.4384)
Δ = 660643.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{660643.84}}{2*25}=\frac{0-\sqrt{660643.84}}{50}
=-\frac{\sqrt{}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{660643.84}}{2*25}=\frac{0+\sqrt{660643.84}}{50}
=\frac{\sqrt{}}{50}
$